b^4-14b^3+40b^2=0

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Solution for b^4-14b^3+40b^2=0 equation:


Simplifying
b4 + -14b3 + 40b2 = 0

Reorder the terms:
40b2 + -14b3 + b4 = 0

Solving
40b2 + -14b3 + b4 = 0

Solving for variable 'b'.

Factor out the Greatest Common Factor (GCF), 'b2'.
b2(40 + -14b + b2) = 0

Factor a trinomial.
b2((4 + -1b)(10 + -1b)) = 0

Subproblem 1

Set the factor 'b2' equal to zero and attempt to solve: Simplifying b2 = 0 Solving b2 = 0 Move all terms containing b to the left, all other terms to the right. Simplifying b2 = 0 Take the square root of each side: b = {0}

Subproblem 2

Set the factor '(4 + -1b)' equal to zero and attempt to solve: Simplifying 4 + -1b = 0 Solving 4 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1b = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1b = 0 + -4 -1b = 0 + -4 Combine like terms: 0 + -4 = -4 -1b = -4 Divide each side by '-1'. b = 4 Simplifying b = 4

Subproblem 3

Set the factor '(10 + -1b)' equal to zero and attempt to solve: Simplifying 10 + -1b = 0 Solving 10 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-10' to each side of the equation. 10 + -10 + -1b = 0 + -10 Combine like terms: 10 + -10 = 0 0 + -1b = 0 + -10 -1b = 0 + -10 Combine like terms: 0 + -10 = -10 -1b = -10 Divide each side by '-1'. b = 10 Simplifying b = 10

Solution

b = {0, 4, 10}

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